Repair or Replace Analysis
Repair or replace analysis compares the cost, risk, performance, supportability, and lifecycle impact of restoring an asset versus replacing it.
What this term means in maintenance
Repair or replace analysis compares the cost, risk, performance, supportability, and lifecycle impact of restoring an asset versus replacing it.
Factors to compare
The review may consider:
- Repair cost
- Replacement cost
- Downtime
- Reliability
- Remaining life
- Energy performance
- Obsolescence
- Spare-parts support
- Safety
- Compliance
- Production demand
Practical example
A 20-year-old compressor requires a major overhaul, has obsolete controls, and consumes excessive energy. Replacement may provide a better lifecycle result.
Decision horizon
The analysis should use a suitable period rather than comparing one repair invoice with the full replacement price.
Risk and business need
Future production, capacity, redundancy, and strategic plans may change the decision.
Common mistake
Using sunk cost or asset age alone can lead to poor decisions.
Related concepts
Related maintenance terms
Keep exploring connected CMMS, reliability, and maintenance planning terms.
Life Cycle Cost
Life Cycle Cost is the total cost of acquiring, operating, maintaining, improving, and disposing of an asset over its useful life.
Remaining Useful Life
Remaining Useful Life is an estimate of how long an asset or component can continue performing acceptably before repair, replacement, or failure.
Obsolescence Management
Obsolescence management is the identification and control of risks created when equipment, components, software, skills, or supplier support are no longer available.
Glossary FAQs
- What should repair-or-replace analysis consider?
Cost, downtime, reliability, remaining life, energy, obsolescence, safety, and business need.
- Is asset age enough?
No. Condition, risk, performance, supportability, and future demand also matter.
- What time horizon should be used?
A period long enough to compare future repair and ownership costs fairly.